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(C) Osmotic pressure $(\pi)$ is a colligative property given by the formula $\pi = iCRT$,where $i$ is the van't Hoff factor,$C$ is the molar concentra

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$KCl < BaCl_2 < AlCl_3 < Al_2(SO_4)_3$

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(C) Osmotic pressure $(\pi)$ is a colligative property given by the formula $\pi = iCRT$,where $i$ is the van't Hoff factor,$C$ is the molar concentration,$R$ is the gas constant,and $T$ is the temperature.Since the solutions are equimolar ($C$ is constant) and at the same temperature,$\pi$ is directly proportional to the van't Hoff factor $(i)$.For complete ionization,$i$ equals the number of ions produced per formula unit:$A$. $KCl \rightarrow K^+ + Cl^-$ $(i = 2)$$B$. $BaCl_2 \rightarrow Ba^{2+} + 2Cl^-$ $(i = 3)$$C$. $AlCl_3 \rightarrow Al^{3+} + 3Cl^-$ $(i = 4)$$D$. $Al_2(SO_4)_3 \rightarrow 2Al^{3+} + 3SO_4^{2-}$ $(i = 5)$Comparing the $i$ values: $2 Therefore,the increasing order of osmotic pressure is $KCl < BaCl_2 < AlCl_3 < Al_2(SO_4)_3$.

Arrange the following equimolar solutions according to increasing order of osmotic pressure [Assume complete ionisation]:
$A$. $KCl$
$B$. $BaCl_2$
$C$. $AlCl_3$
$D$. $Al_2(SO_4)_3$

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Arrange the following equimolar solutions according to increasing order of osmotic pressure [Assume complete ionisation]:$A$. $KCl$$B$. $BaCl_2$$C$. $AlCl_3$$D$. $Al_2(SO_4)_3$